Given a 32-bit signed integer, reverse digits of an integer.<\/p>\n
Example 1:<\/strong><\/p>\n Example 2:<\/strong><\/p>\n Example 3:<\/strong><\/p>\n Note:<\/strong> Python<\/strong><\/p>\nInput:<\/strong> 123\r\nOutput:<\/strong> 321\r\n<\/pre>\n
Input:<\/strong> -123\r\nOutput:<\/strong> -321\r\n<\/pre>\n
Input:<\/strong> 120\r\nOutput:<\/strong> 21\r\n<\/pre>\n
\nAssume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [\u2212231<\/sup>,\u00a0 231\u00a0<\/sup>\u2212 1]. For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.<\/p>\n \r\nclass Solution(object):\r\n def reverse(self, x):\r\n """\r\n :type x: int\r\n :rtype: int\r\n """\r\n list_x = list(str(x))\r\n temp = list_x[::-1]\r\n if temp[len(temp)-1] is "-":\r\n temp.pop()\r\n flag = "-"\r\n for i in temp:\r\n flag += i\r\n return self.return_num(flag)\r\n else:\r\n flag = ""\r\n for i in temp:\r\n flag += i\r\n return self.return_num(flag)\r\n\r\n def return_num(self, num):\r\n if int(num) > (2 ** 31) or int(num) < -(2 ** 31):\r\n return 0\r\n else:\r\n return int(num)\r\n<\/pre>\n","protected":false},"excerpt":{"rendered":"