Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.
- push(x) — Push element x onto stack.
- pop() — Removes the element on top of the stack.
- top() — Get the top element.
- getMin() — Retrieve the minimum element in the stack.
Example:
MinStack minStack = new MinStack(); minStack.push(-2); minStack.push(0); minStack.push(-3); minStack.getMin(); --> Returns -3. minStack.pop(); minStack.top(); --> Returns 0. minStack.getMin(); --> Returns -2.
Python
class MinStack(object):
def __init__(self):
"""
initialize your data structure here.
"""
self.min_stack = []
self.min_num_stack = []
def push(self, x):
"""
:type x: int
:rtype: void
"""
if len(self.min_num_stack) == 0 or x <= self.min_num_stack[-1]:
self.min_num_stack.append(x)
self.min_stack.insert(0, x)
def pop(self):
"""
:rtype: void
"""
if self.min_stack[0] == self.min_num_stack[-1]:
self.min_num_stack.pop()
del self.min_stack[0]
def top(self):
"""
:rtype: int
"""
return self.min_stack[0]
def getMin(self):
"""
:rtype: int
"""
return self.min_num_stack[-1]