Given a binary array, find the maximum number of consecutive 1s in this array.
Input: [1,1,0,1,1,1] Output: 3 Explanation: The first two digits or the last three digits are consecutive 1s. The maximum number of consecutive 1s is 3.
- The input array will only contain
- The length of input array is a positive integer and will not exceed 10,000
class Solution(object): def findMaxConsecutiveOnes(self, nums): """ :type nums: List[int] :rtype: int """ maximum = 0 imum = 0 for i in nums: if i == 1: imum += 1 maximum = max(maximum, imum) else: imum = 0 return maximum